Calculate the acceleration of the moon towards earth’s center `(AS_(1))`

Calculate the value of ‘g' at height ‘h' from the earth’s surface.

The mass of the moon is 1/(80) th of the mass of the earth and its radius is 1/4 th of that of the earth. Compare the accelerations due to gravity on the earth's and the moon's surface

Mass of the earth is 81 times has mass of the moon. The distance between earth and moon is 4xx10^5 km. calculate the position of the point on the line joining the centres of earth and moon where the gravitational field is zero.

If both the radius and the mean density of a planet are half the radius and the mean density of the earth, what will be the acceleration due to gravity on the surface of that planet ? Given that the acceleration due to gravity on the earth's surface =980 cm*s^(-2)

Define acceleration due to gravity. Deduce an expression of the acceleration of the acceleration due to gravity at a place on the surface of the earth due to its rotating.

The mass of the moon is 1/(80) th of that of the earth and the radius of the moon is 1/4 th of that of the earth. The ratio of the acceleration due to gravity on the moon and that on the earth is

What is the value of the acceleration due to gravity at the centre of the earth ?

The average distance of the sun from the earth is 1.5xx10^8 km and the average distance of the moon from the earth is 384000 km. if the attraction of the sun on the earth is 180 times the attraction of the moon ,how many times is the mass of the sun greater than that of the moon ?

IF g is the acceleration due to gravity on the earth's surface , then at a depth x acceleration due to gravity will be g (1- ( x) /( R )) - prove it . [ R is the radius of the earth ]