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A cyclist is riding with a speed of 27 k...

A cyclist is riding with a speed of 27 km /h . As he approaches a circular turn on the road of radius 80 m , he applies brakes and reduces his speed at the constant rate of `0.50m//s` every second . What is the magnitude and direction of the net acceleration of the cyclist on the circular turn ?

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The correct Answer is:
`0.86 " m s"^(-2),54.5^(@)` with the direction of velocity
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