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Examine Tables 6.1-6.3 and express The...

Examine Tables 6.1-6.3 and express
The kinetic energy of an air molecule `(10^(-21)J)` in eV.

Text Solution

Verified by Experts

The kinetic energy of an air molecule is
`(10^(-21)J)/(1.6xx10^(-19)J"/"eV) cong 0.0062 eV`
This is the same as 6.2 meV.
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