Home
Class 11
PHYSICS
An elevator can carry a maximum load of ...

An elevator can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of `2ms^(-1)`. The frictional force opposing the motion is 4000 N. Determine the minimum power delivered by the motor to the elevator in watts as well as in horse power.

Text Solution

Verified by Experts

The downward force on the elevator is `F= mg+ F_(f)= (1800xx10)+ 4000= 22000N`
The motor must supply enough power to balance this force. Hence,
`P= F*v= 22000xx2= 44000 W = 59 hp`.
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    NCERT BANGLISH|Exercise EXERCISES|44 Videos

  • WORK, ENERGY AND POWER

    NCERT BANGLISH|Exercise EXERCISES (ADDITIONAL EXERCISES)|6 Videos

  • WAVES

    NCERT BANGLISH|Exercise Exercises|26 Videos

Similar Questions

Explore conceptually related problems

A motor boat is moving at a steady speed of 36.km*h^(-1) . If the water resistance to the motion of boat is 4000N, calculate the power of the engine.

A railway engine of mass 12,000 kg is moving at constant speed of 5m*s^(-1) up an inclined of 15^@ . Calculate the power of the engine. Given g=9.8 m*s^(-2) .

A car of mass 500 kg is moving up along an inclined surface of slope 1/(25) at a constant speed of 72 km*h^(-1) . If the coefficient of friction between the road and the car wheel is 0.1 , find the power of the car engine (g= 9.8 m*s^(-2) ).

An engine, working at a constant rate, is pulling a train of mass 500 tonne along a plane of inclination sin ^(-1) (1/(100)) . If the frictional force per metric tonne is 49 N and the train is moving with a velocity of 10 m *s^(-1) , what is the power of the engine in kilowatt ? [ 1 tonne (metric ton) =1000 kg]

Calculate the power of an engine which can maintain a speed of 50 "m.s"^(-1) for a train of mass 3xx10^(6) kg on a rough level track. The coefficient of friction is 0.05. Given g = 10 "m.s"^(-2)