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A pure inductor of 25.0 mH is connected ...

A pure inductor of 25.0 mH is connected to a source of 220 V. Find the inductive reactance and rms current in the circuit if the frequency of the source is 50 Hz.

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The inductive reactance,
`X_(L)=2pi vL=2xx3.14xx50xx25xx10^(-3)Omega`
`=7.85Omega`
The rms current in the circuit is
`I=(V)/(X_(L))=(220V)/(7.85Omega)=28A`
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NCERT BANGLISH-ALTERNATING CURRENT-ADDITIONAL EXERCISES
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