One of the roots of the Q.E. `6x^(2) - x - 2 = 0` is

Product of the roots of the Q.E. 3x^(2) - 6x + 11 = 0 "is"

One solution of the Q.E. 2x^(2) - 5x - 3 = 0 is

One of the roots of the equation x^2 - 6x + k=0 is x = 2. The other root is:

The roots of the Q.E. (x -1/3)^(2) = 9

The roots of the Q.E. (7x - 1)(2x + 3) = 0 are

If the sum of the roots of the Q.E. 3x^(2) + (2k + 1) x - (k + 5) = 0 is equal to the product of the roots, then the value of k is

The roots of the Q.E. sqrt 3 x^(2) -2x - sqrt 3 = 0 "are"

A: The equation whose roots are the reciprocals of the roots of 2x^(3) + 7x^(2) - 6x + 1 = 0 is x^(3) - 6x^(2) + 7x + 2 =0 . R: the equation whose roots are the reciprocals of those of f(x) = 0 is f(1/x) = 0.

The sum of the roots of the equation x^(2)-6x+2=0 is

If one of the roots of the equation 2x^(2)-6x+k=0 is ((alpha+5i)/(2)), then the values of a and k are