Let `p, q, r, s in R, x^2 + px + q = 0, x^2 + rx + s = 0` such that `2 (q + s) = pr` then

if P,q, r, s in R such that p r= 2 ( q+ s) then

If p, q, r, s in R , then equaton (x^2 + px + 3q) (-x^2 + rx + q) (-x^2 + sx-2q) = 0 has

If every pair from among the equations x^ 2 + p x + q r = 0, x^2+px+qr=0, x^2 + q x + r p = 0, x^2+qx+rp=0 and x^2 + r x + p q = 0, x^2+rx+pq=0 has a common root then the product of three common root is (A) pqr (B) 2pqr (C) (p^2q^2r^2) (D)none of these

Let P = { x : x in R , |x| Q = {x:x in R , |x -1 |ge 2} P uu Q = R - S then set S is : (where R is the set of real number)

Let P = { x : x in R , |x| Q = {x:x in R , |x -1 |ge 2} P uu Q = R - S then set S is : (where R is the set of real number)

Let p and q be the roots of x^2 - 2x + A =0 and let r and s be the roots of x ^2 - 18 + B =0 . If p lt q lt r lt s are in ordered pair (A , B) =

If p, q, r, s are in G.P. then show that (q -r )^(2) + ( r -p) ^(2) + ( s-q) ^(2) = ( p -s) ^(2)

If p + r = 2q and 1/q + 1/s = 2/r , then prove that p : q = r : s .

If alpha, beta are the real roots of x^(2) + px + q= 0 and alpha^(4), beta^(4) are the roots of x^(2) - rx + s = 0 , then the equation x^(2) - 4 q x + 2q^(2) - r = 0 has always