The coordinates of the two ends of latus rectum of a parabola are (3,4) and (3,0) ,find the equation of the parabola.

The coordinates of the two ends of latus rectum of a parabola are (8,1) and (-4,1) , find the equation of the parabola.

If two ends of latus rectum of a parabola are the points (3,6) and (5,6), then equation of the parabola is

Two ends of the latus rectum of a parabola are (4,6) and (-2,6), then the equation of one of the parabola is

The extreme points of the latus rectum of a parabola are (7,5) and (7,3). Find the equation of the parabola and the points where it meets the coordinate axes.

The vertex of a parabola is (2, 2) and the coordinats of its two extremities of latus rectum are (-2,0) and (6, 0). Then find the equation of the parabola.

The vertex of a parabola is (2, 2) and the coordinats of its two extremities of latus rectum are (-2,0) and (6, 0). Then find the equation of the parabola.

The vertex of a parabola is (2,2) and the coordinats of its two extrremities of latus rectum are (-2,0) and (6,0). Then find the equation of the parabola.

The vertex of a parabola is (2, 2) and the coordinats of its two extremities of latus rectum are (-2,0) and (6, 0). Then find the equation of the parabola.

The vertex of a parabola is (2, 2) and the coordinats of its two extremities of latus rectum are (-2,0) and (6, 0). Then find the equation of the parabola.

The ends of latus rectum of parabola x^2+8y=0 are