The equation of the perpendicular bisector of line `AB` is `x+2y=8` and the co-ordinates of point `A` are `(1,1)`. Co-ordinates of `B` are :

The line x-4y =6 is the perpendicular bisector of the line segment AB. If B= (1, 3), find the co-ordinates of point A.

The equation of the perpendicular bisector of the side AB of a triangle ABC is x-y+5=0 . If the point A is (1,2) , find the co-ordinates of the point B .

The cartesian co-ordinates of a point are (1, -1) , its polar co - ordinates are

The equation of the perpendicular bisector of the side AB of a triangle ABC is x - y + 5 = 0. If the point A is (1,-2), find the co-ordinates of the point B.

(a) Find the polar co-ordinates of a point Cartesian co-ordinates are (-1,1) .

Find the perpendicular bisector of AB, where the co-ordinates of A and B are (0, -5) and (2,- 3) respectively.

x-3y-5=0 is the perpendicular bisector of the line segment joining the points A,B. If A=(-1,-3) , find the co ordinates of B.

Let A, B and C be the vertices of a triangle, equation of perpendicular bisectors of AB and AC are x-y +3 =0 and x+2y + 12=0 respectively If co-ordinates of A are (2,3), then equation of BC is

D is the midpoint of line segment AB. The co-ordinates of A and D are (2, 4) and (-1, 3), respectively. The co-ordinates of B are: