For an EMWave,
`E = E_(0)sin 12 xx 10^(6) [Z-2xx10^(8)t]N/C`
in a medium, then its refractive index is

For and EMWave . E= E_(0) sin 12 xx 10^(6) [X -2 xx 10^(8) t ] (N)/(C ) in a medium then its refractive index is -

An electromagnetic wave travelling through a transparent medium is given by E_(x)(y,t)=E_(ax)sin2pi[y/(5xx10^(-7))-3xx10^(14)t] in SI unit then the refractive index of medium is,

An electromagnetic wave travelling through a transparent medium is given by E_(x)(y,t)=E_(ax)sin2pi[y/(5xx10^(-7))-3xx10^(14)t] in SI unit then the refractive index of medium is,

A place electromagnetic wave E_z = 100 cos(4 \times10^-7 z - 50 t) V/m propagates in a medium. Find the refractive index of the medium.

A light wave has a frequency of 4xx10^(14)Hz and a wavelength of 5xx10^(-7) meters in a medium. The refractive index of the medium is

A light wave has a frequency of 4xx10^(14)Hz and a wavelength of 5xx10^(-7) meters in a medium. The refractive index of the medium is

Electric field of one plane progresive electromagnetic wave is E_(Z)=100 cos (6xx10^(8)t + 4x)Vm^(-1) . Then refreactive index of medium pf propagation would be …..

If speed of light in a medium is 2xx10^8m//sec . Find refractive index of medium.