Home
Class 9
PHYSICS
A car travels from rest with a constant ...

A car travels from rest with a constant acceleration 'a' for 't' seconds. What is the average speed of the car for its journey if the car moves along a straight road?

Text Solution

Verified by Experts

The car starts from rest, so u = 0 The distance covered in time t
s = `(1)/(2) at^(2) `
Average speed = `(" Total distance " )/("Time taken " )`
`v = (("at"^(2)))/(t)`
= `(at)/(2) `
Promotional Banner

Topper's Solved these Questions

  • MOTION

    NCERT KANNAD|Exercise LET US IMPROVE OUR LEARNING (REFLECTIONS ON CONCEPTS )|1 Videos
  • MOTION

    NCERT KANNAD|Exercise LET US IMPROVE OUR LEARNING(APPLICATION OF CONCEPTS)|6 Videos
  • MATTER AROUND US

    NCERT KANNAD|Exercise Let us Improve our learning (Suggested project)|1 Videos
  • REFRACTION OF LIGHT AT PLANE SURFACES

    NCERT KANNAD|Exercise II. Application of concepts|1 Videos

Similar Questions

Explore conceptually related problems

A car starts from rest and moves with constant acceleration. The ratio of distance covered by the car in nth second with that covered in n seconds is:

A car moves from A to B with a speed of 30 kmph and from B to A with a speed of 20 kmph. What is the average speed of the car ?

A body starting from rest moves with constant acceleration 'a'. This acceleration is a pr where p is a constant. What is the displacement of particle in a time interval=0 to t = t_1 ?

A car accelerates from rest at a constant rate a for some time after which it retards at a constant rate to come to rest. If the time elapsed is t, maximum velocity reached is

A car is moving with the accelaration 2 m/ s^(2) from rest. Find the distance traveled by the car in 10th second.