Home
Class 11
PHYSICS
Let us consider an equation (1)/(2)mv^(2...

Let us consider an equation `(1)/(2)mv^(2)=mgh`
Where m is the mass of the body. V its velocity , g is the acceleration due to gravity and h is the height . Check whether this equation is dimensionally correct.

Text Solution

Verified by Experts

The dimensions of LHS are
`[M] [L T^(-1)]^(2) = [M] [L^(2)T^(-2)]`
`=[M L^(2) T^(-2)]`
The dimensions of RHS are
`[M][L T^(-2)] [L] = [M][L^(2) T^(-2)]`
`=[M L^(2) T^(-2)]`
The dimensions of LHS and RHS are the same and hence the equation is dimensionally correct.
Promotional Banner

Similar Questions

Explore conceptually related problems

The acceleration due to gravity becomes (g/2) where g = acceleration due to gravity on the surface of the earht at a height equal to

The period of oscillation (T) of a simple pendulum depends on the probable quantities such as mass 'm' of a bob, length 'l' of the pendulum and acceleration due to gravity 'g' at the place. Derive an equation using dimensional analysis.

A quantity X is given by (me^(4))/(8epsilon_(0)^(2)ch^(3)) where m is mass of electron, e is the charge of electron, epsilon_(0) is the permittivity of free space, c is the velocity of light and h is the Planck's constant. The dimensional formula for X is the same as that of :

A rubber ball is dropped from a height of 5 m on a planet where the acceleration due to gravity is not known. On bouncing it rises to 1.8 m. The ball loses its velocity on bouncing by a factor of: