A bob of mass m is suspended by a light string of length L. It is imparted a horizontal velocity `v_(o)` at the lowest point A such that it completes a semi-circular trajectory in the vertical plane with the string becoming slack only on reaching the topmost point, C. This is shown in Fig. Obtain an expression for
The ratio of the kinetic energies `(K_(B)"/"K_(C ))` at B and C.

Explanation

The ratio of the kinetic energies at B and C is :
`(K_B)/(K_C)=((1)/(2)mv_(B)^(2))/((1)/(2)mv_(c )^(2))=(3)/(1)`