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In a plane electromagnetic wave, the ele...

In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of `2.0 xx 10^(10) Hz` and amplitude `48 V m^(–1)`.
(a) What is the wavelength of the wave?
(b) What is the amplitude of the oscillating magnetic field?
(c) Show that the average energy density of the E field equals the average energy density of the B field. `[c = 3 xx 10^(8) m s^(-1).]`

Text Solution

Verified by Experts

(a) `lamda =(c//v) =1.5 xx10^(-2) m`
(b) `B_(0)=(E_(0)//c)=1.6 xx10^(-7) T`
(c ) Energy density in E field: `u_(E) =(1//2)epsi_(0) E^(2)`
Using `E= cB, and c=(1)/(sqrt(mu_(0) epsi_(0)), u_(E)=u_(B)`
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Knowledge Check

  • In a plane e.m. wave, the electric field oscillates sinusoidally at a frequency of 2.5 xx 10^(10) Hz and amplitude 480V // m . The amplitude of oscillating magnetic field will be:

    A
    `1.52 xx 10^(-8) Wb // m^(2)`
    B
    `1.52 xx 10^(-7) Wb // m^(2)`
    C
    `1.6 xx 10^(-6) Wb // m^(2)`
    D
    `1.6 xx 10^(-7) Wb // m^(2)`
  • The amplitude of electric and magnetic fields related to each other are :

    A
    `E_(0)=B_(0)`
    B
    `E_(0)=cB_(0)`
    C
    `E_(0)=B_(0) // c`
    D
    `E_(0)=c // B_(0)`
  • In electromagnetic wave, the average energy density is associated to:

    A
    electric field only
    B
    magnetic field only
    C
    equally with electric and magnetic field
    D
    average energy density is zero.
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