Prove that the curves `x = y^(2)` and xy = k cut at right angles* if `8k^(2) = 1`.

The curve x = y^(2) and xy = k cut at right angles if

The curves x = y^(2) and xy = a^(3) cut orthogonally at a point, then a^(2) =

The lines joining the origin to the point of intersection of the curves x^(2)+y^(2)+2gx+c=0 and x^(2)+y^(2)+2fy-c=0 are at right angles if

If the curves y^(2) = 16x and 9x^(2)+by^(2) =16 cut each other at right angles, then the value of b is

The angle between the curves y^(2) =x and x^(2) = y at (1,1) is

If te curves 2x=y^(2) and 2xy=K intersect perpendicularly, then the value of K^(2) is

Angle of intersection of the curves y = 4-x^(2) and y = x^(2) is

The angle between the curves xy = 2 and y^2 = 4x at their point of intersection is

If the lines joining the origin to the points of intersection of the line 2x+y-1 =0 and the curve 3x^(2)+lambdaxy-4x+1=0 are at right angles then

The angle of intersection of the curves x^(2)+y^(2)=8 and x^(2)=2y at the point (2, 2) is