Home
Class 11
CHEMISTRY
A compound has the following composition...

A compound has the following composition Mg = 9.76%,S = 13.01%, 0 = 26.01, `H_2O` = 51.22, what is its empirical formula?
[Mg = 24, S = 32, O = 16, H = 1]

Text Solution

Verified by Experts


Hence the empirical formula is Mg `SO_4 .7 H_2O`.
Promotional Banner

Similar Questions

Explore conceptually related problems

A compound has the following composition Mg = 9.76%, S = 13.01 %, O=26.01, H_(2)O = 51.22% , What is its emperical formula [Mg = 24, S=32, O=16, H=1]

A substance on analysis, gave the following percentage composition, Na = 43.4%, C = 11.3%, 0 = 45.3% calculate its empirical formula [Na = 23, C = 12, O = 16].

An organic compound on analysis gave the following composition : C = 57.8% H = 3.6% and rest is oxygen. Its empirical formula is :

A compound on analysis gave the following percentage composition: Na=14.31% S = 9.97%, H = 6.22%, O = 69.5%, calcualte the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, S = 32, H = 1, 0 = 16].

An orgainc compound contains 43.98% C , 2.09% H , and 37.2% Cl . Calculate its empirical formula.

A substance used as a water softener has the following mass percentage composition : 42.07% Na, 18.9% P , and 39.04% of oxygen. Determine the empirical formula of the compound. (Na = 23, P = 31, 0 = 16)

An inorganic substance has the following composition: N = 35% H = 5%, O = 60 % On being heated, it yielded a gaseous compound containing N = 63.63% and O = 36.37% . Suggest a formula for each substance and equation for the chemical change.