[Cu(NH3)4]^(2+) is square planar, where...

`[Cu(NH_3)_4]^(2+)` is square planar, where as `[NiCl_(4)]^(2-)` is tetrahedral. Explain.

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The square planar [Ni(CN)_(4)]^(2-) complex :

The magnetic moment (spin only) of [NiCl_(4)]^(2-) is :

The complex [Cu(NH_(3))_(4)]^(2+) is :

Amongst Ni(CO)_(4), [Ni(CN)_(4)]^(2-) and [NiCl_(4)]^(2-) :

[NH(CH_2)_4NHCO(CH_2)_4CO]_4 is a :

The oxidation number of Nickel in the complex ion, [NiCl_4]^(2-) is

The hybridization states of [Ni(CO)_(4)], [Ni(CN)_(4)]^(2-) and [NiCl_(4)]^(2-) species are respectively

The IUPAC name of [Ni(NH_(3))_(4)] [NiCl_(4)] is :

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