0.1978 g of copper is deposited by a current of 0.2 ampere in 50 minutes. What is the electrichemical equivalent of copper ?

Explanation

Here, t = 50 minutes `=50xx60` seconds , I = 0.2 ampere
Quantity of electricity used is
`Q=Ixxt=0.2xx50xx60=600" coulomb"`
Amount of copper deposited by 600 coulombs = 0.1978 g
Amount of copper deposited by 1 coulomb `=(0.1978)/(600)g=0.0003296g`
Electrochemical equivalent of copper `=0.0003296=3.296xx10^(-4)gc^(-1)`
`=3.206xx10^(-7)kgc^(-1)`