A uniform disc is rolling on a horizontal surface. At a certain instant `B` is the point of contact and `A` is at height `2 R` from ground, where `R` is radius of disc -
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A disc is rolling on a rough horizontal surface. The instantaneous speed of the point of contact during perfect rolling is zero with respect to ground. The force of friction can help in achieving pure rolling condition.

A uniform circular disc of radius R is rolling on a horizontal surface. Determine the tangential velocity : at the upper most point

A uniform circular disc of radius R is rolling on a horizontal surface. Determine the tangential velocity : the centre of mass

A uniform circular disc of radius R is rolling on a horizontal surface. Determine the tangential velocity (i) at the upper most point (ii) at the centre of mass and (iii) at the point of contact.

A uniform disc of radius R is in pure rolling on a fixed horizontal surface with constant speed v_0 as shown in the figure. For what value of theta , speed of point P will be v_0/2√(5+2√3) ? (OP= R/2 and O is the centre of disc)

A disc shaped body (having a hole shown in the figure) of mass m=10kg and radius R=10/9m is performing pure rolling motion on a rough horizontal surface. In the figure point O is geometrical center of the disc and at this instant the centre of mass C of the disc is at same horizontal level with O . The radius of gyration of the disc about an axis pasing through C and perpendicular to the plane of the disc is R/2 and at the insant shown the angular velocity of the disc is omega=sqrt(g/R) rad/sec in clockwise sence. g is gravitation acceleration =10m//s^(2) . Find angular acceleation alpha ( in rad//s^(2) ) of the disc at this instant.

A disc shaped body (having a hole shown in the figure) of mass m=10kg and radius R=10/9m is performing pure rolling motion on a rough horizontal surface. In the figure point O is geometrical center of the disc and at this instant the centre of mass C of the disc is at same horizontal level with O . The radius of gyration of the disc about an axis pasing through C and perpendicular to the plane of the disc is R/2 and at the insant shown the angular velocity of the disc is omega=sqrt(g/R) rad/sec in clockwise sence. g is gravitation acceleration =10m//s^(2) . Find angular acceleation alpha ( in rad//s^(2) ) of the disc at this instant.

A disc of radius 0.2 m is rolling with slipping on a flat horizontal surface, as shown in Fig. The instantaneous centre of rotation is (the lowest contact point is O and centre of disc is C )