If H.C.F(225,60)=225x5-`10x` then `x=`

If H.C.F. of 135 and 225 is 45, then find their L.C.M.

If H.C.F. of 13 and 225 is 45, then their L.C.M. is :

If (3^(2x-8))/(225)=(5^(3))/(5^(x)), then x=2( b) 3(c)5(d)4

If (3^(2x-8))/(225)=(5^3)/(5^x) , then x= (a) 2 (b) 3 (c) 5 (d) 4

Let f:(0,oo)rarr R and F(x)=int_(0)^(x)t.f(t)dt. If F(x^(2))=x^(4)+x^(5), then sum_(r=1)^(12)f(r^(2)) equals (A) 216(B)219 (C) 221(D)225

Given that HCF (135,225)=45 find the LCM (135,225)

If f(x)=(x^2-10x+25)/(x^2-7x+10) for x!=5 is continuous at x=5 then f(5)=

2.45x + 1.5 = 3.7x - 2.25 then x=_____