(-5)/(7)+(-6)/(-7)

(1)/(5)xx(5)/(7)div (6)/(7)=?

The probability that a non-leap year has 53 sundays,is (2)/(7) (b) (5)/(7)(c)(6)/(7) (d) (1)/(7)

( (5)/(6)-:(6)/(7)times(6)/(7)-(8)/(9)-:1(3)/(5)+(3)/(4)times3(1)/(3)

What is the value of ((5)/(7) of (19)/(6))/((19)/(7)/((7)/(4)))

Simplify 2/5+3/7+((-6)/5)+((-13)/7)

(343xx49)/(216xx16xx81)=?(7^(5))/(6^(7))(b)(7^(5))/(6^(8))(c)(7^(4))/(6^(7)) (d) (7^(6))/(6^(7))(e) None of these

Evaluate the following: (3/7)^(-5)xx(7/6)^(-4)