If the coefficient of linear expansion of iron is `1.20xx10^-5K^(-1)` and diameters of the wooden and the iron rings are `1.472m` and `1.398m`, then calculate the temperature to which the iron ring has to be heated from `27^(@)`C, so that the iron ring fits over the wooden ring.

Coefficient of linear expansion of iron is 12 times 10^(-6@)C^(-1) - explain the statement.

The coefficient of linear expansion of iron is 0.000011.^(@)C . An iron ro is 10 metre long at 27^(@)c . The length of the rod will be decreased by 1.1 mm when the temperature of the rod changes to

A blacksmith fixes Iron ring on the rim of the wooden wheel of a horse cart. The diameter of the rim and the fron ring are 5.243 m " and " 5.231 m, respectively at 27 ^(@)C . To what temperature should the ring be heated so as to fit the rim of the wheel?

An iron metre rod is allowed an error of 1 part per milliion. If the coefficient of linear expansion of ironis 1xx10^(-5).^(@)C^(-1) , what is the maximum variation in temperature that the rod could have?

A blacksmith fixes Iron ring on the rim of the wooden wheel of a horse cart. The diameter of the rim and the fron ring are 5.243 m " and " 5.231 m, respectively at 27 ^(@)C . To what temperature should the ring be heated so as to fit the rim of the wheel?(linear coefficient of expansion=1.20*10^-5 /K)

The diameter of a metal ring is D and the coefficient of linear expansion is alpha . If the temperature of the ring is increased by 1^(0)C , the circumference and the area of the ring will increases by