समीकरण `(x-8)/(3x-2)=(3x+4)/(2x+1)` को सरल कीजिये।

If (8/3)^(3-x) = (3/8 )^(2x-1) , then x =

Find x: 2^(3x)=8^(2x+1)

(e) (2x-3)/2 + ( 2x +(3x -1)/4) = 1/8

4x-[3x-(1-5x)-6{8-3(2x+7)]}

If x ne -1,2 and 5, then the simplified value of {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) is equal to : यदि x ne -1,2 और 5 है, तो {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) का सरलीकृत मान क्या होगा ?

If x≠ − 1 , 2 and 5, then the simplified value of {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} is equal to: यदि x≠ − 1 , 2 और 5 है तो {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} का सरलीकृत मान बराबर हैः

Solve for x: (3x+8)/(4)-2x=(3x+2)/2+4

if (5x)/(4) + (3x)/(8) gt (39)/(8) " and " (2x-1)/(12)-(x-1)/(3)lt(3x+1)/(4) , then x belongs to the internal