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If omega(!=1) is a cube root of unity, ...

If `omega(!=1)` is a cube root of unity, and `(1""+omega)^7=""A""+""Bomega` . Then (A, B) equals (1) (0, 1) (2) (1, 1) (3) (1, 0) (4) `(-1,""1)`

A

0,1

B

1,1

C

1,2

D

`-1,1`

Text Solution

Verified by Experts

The correct Answer is:
B
`(1+omega)^7=(1+omega)(1+omega)^6`
`=(1+omega)(-omega^2)^6=1+omega`
`rArr " "A+Bomega=1+omega`
`rArr" "A=1,B=1`
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