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Three boys and two girls stand in a queu...

Three boys and two girls stand in a queue. The probability, that the number of boys ahead is at least one more than the number of girls ahead of her, is

A

`1//2`

B

`1//3`

C

`2//3`

D

`3//4`

Text Solution

Verified by Experts

The correct Answer is:
A
Total number of ways to arrange 3 boys and 2 girls are 5!.
According to given condition, following cases may mise.
`{:(B" "G" "G" "B" "B),(G" "G" "B" "B" "B),(G" "B" "G" "B" "B),(G" "B" "B" "G" "B),(B" "G" "B" "G" "B):}`
So number of favorite ways `=5xx3!xx2! =60`
`therefore " Required probility " =(60)/120)=1/2`
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