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Six boys and six girls sit in a row rand...

Six boys and six girls sit in a row randomly. Find the probability that (i) the six girls sit together, (ii) the boys and girls sit alternately.

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The total number of arrangementa of six boys and six girls = 12 !
`therefore` Required probability `=(6!xx7!)/((12!))=1/132`
[since, we consider six girls at one person] (ii) Required probability `=(2xx 6! Xx 6! )/(12!)=1/462 `
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