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One Indian and four American men and their wives are to be seated randomly around a circular table. Then the conditional probability that the Indian man is seated adjacent to his wife given that each American man is seated adjacent to his wife is

A

`(1)/(2)`

B

`(1)/(3)`

C

`(2)/(5)`

D

`(1)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
C

Let E= event when each American man is seated adjacent to his wife
and A=event when Indian man is seated adjacent to his wife
Now , `n(A cap E ) =(4!) xx (2!)^(5)`
Even when each American man is seated adjacent to his wife.
Again , ` n(E)=(5!)xx(2!)^(4)`
`:. P""((A)/(E)) =(n(A cap E ))/(n(E)) =((4!)xx(2!)^(5))/((5!)xx(2!)^(4))=(2)/(5)`
Alternate solution
Fixing four American couples and one Indian man in between any two couples , we have 5 different ways in which his wife can be seated , of which 2 cases are favourable.
`:.` Required probability `=(2)/(5)`
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