An unbiased die with faced marked 1, 2, 3, 4, 5, and 6 is rolled four times. Out of four face value obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than five is then

Options

A. `16/81`
B. `1/81`
C. `80/81`
D. `65/81`

Answer

A

Explanation

Let A=getting not less than 2 and not greater than 5
`implies A={2,3,4,5} implies P(A) =(4)/( 6)`
But die is rolled four times , therefore the probability in getting four throws
`((4)/(6))((4)/(6))((4)/(6))((4)/(6))=(16)/(81)`