The directrix of a parabola is `x+y+4=0` and vertex is at `(-1,-1).` find the position of the of the focus and the equation of parabola.

The directrix of a parabola is x+y+4=0and vertex is at (-1,-1).Find the position of the focus and the equation of parabola.

The directrix of a parabola is x + y + 4 = 0 and vertix is the point (-1,-1) . Find (i) the position of focus and (ii) the equation of the parabola.

The equation of the directrix of a parabola is x = y and the coordinates of its focus ar (4,0) . Find the equation of the parabola.

The vertex of a parabola is (a,0) and the directrix is x+y=3a. The equation of the parabola is

The vertex of a parabola is (a,0) and the directrix is x+y=3a the equation of the parabola is

Find the equation of the parabola with vertex is at (2,1) and the directrix is x=y-1.

The vertex of the parabola is (4,0) and the y -axis is the directrix. Then the focus is

Find the equation of the parabola with vertex is at (2,1) and the directrix is x=y-1 .

The line x-1=0 is the directrix of a parabola, y^2=kx then Find the vertex, focus,axis of parabola and length of latus rectum of the parabola.

The focus and directrix of a parabola are (1 2) and 2x-3y+1=0 .Then the equation of the tangent at the vertex is