Each of the two point charges are doubled and their distance is halved. Force of interaction becomes n times where n is

The mass of two bodies are doubled and the distance is halved, how will the gravitational force change?

Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

If the distance between two point charges is doubled and their individual charges are also doubled, what would happen to the force between them.

[" Two charges of equal magnitude "],[" and at a distance 'r' exert a force 'F' "],[" on each other.If one of the charges "],[" doubled and distance between them "],[" is halved,the new force acting on "],[" each charge is "],[[" (A) "(F)/(8)],[" (B) "(F)/(4)],[" (C) ",8F],[" (D) "(F)/(16)]]

Three capacitors of capacity C each are joined first in series and then in parallel. The capacity becomes n times where n is—