A photoelectron is moving with a maximum velocity of `10^(6) m//s`. Given `e=1.6xx10^(-19) c`, and `m=9.1xx10^(-31) kg`, the stopping potential is

The maximum velocity of photoelectronos emitted hy a photoemitter is 1.8 xx 10^(6) m//sec . Taking e//m = 1.8 xx 10^(11) C/kg for electrons, the stopping potential of the emitter is:

An electron is moving with a velocity of 10^(7) m s^(-1) . Find its energy in electron volts. (Mass of electron =9.1xx10^(-31) kg and charge of electron =1.6xx10^(-19) C )

Calculate the gyro magnetic ratio of electron (given 1.6 xx10^(-19) C, m_r=9.1xx10^(-3) kg )

Calculate the gyromagnetic ratio of electron (Given e = 1.6xx10 T^-19 C, m_e = 9.1xx10^-31 kg)

A radiation of 3300 Å falls on a metal to eject electrons with a maximum velocity of 0.4 xx10^6 m//s, the value of the work function of metal is nearly (h=6.6 xx10^-34J-s,m_e =9.1 xx10^-31 kg)

A radiation of 3300 Å falls on a metal to eject electrons with a maximum velocity of 0.4 xx10^6 m//s, the value of the work function of metal is nearly (h=6.6 xx10^-34J-s,m_e =9.1 xx10^-31 kg)

The maximum velocity of ejected photoelectrons 2 xx 10^6 m/sec and (e/m) of electrons is 1.8 xx 10^11 coul/kg. The stopping potential in volts is