`(cos theta+isintheta)^(n)=cosntheta+isin n theta` सभी प्राकृतिक संख्याओं के लिए `n`

(cos3theta+isin3theta)^5/(costheta+isintheta)^6

(cos theta + i sin theta) ^ (n) = cos n theta + i sin n theta

If (1+costheta+isintheta)(1+cos2theta+isin2theta)=x+iy then y =

Prove, by induction, that (cos theta + isintheta)^n = cos n theta + isin ntheta for all positive as well as negative integral values of n

If n is an integer then show that (1 + cos theta + i sin theta)^(n) + (1 + cos theta - i sin theta )^(n) = 2^(n+1) cos ^(n) ( theta//2) cos ((n theta)/2) .

If (1+costheta-isintheta)(1+cos2theta+isin2theta)=x+iy then x^2+y^2 =

Prove that (costheta+isintheta)^n=cosntheta+isinntheta by P.M.I. where n is a pos integer.

If (costheta +isintheta)(cos2theta +isin2theta).....(cosntheta + isinntheta) = 1 then the value of theta is:

If (costheta +isintheta)(cos2theta +isin2theta).....(cosntheta + isinntheta) = 1 then the value of theta is: