A hydrocarbon `X` has molecular formula `C_(8)H_(18).` Substitution of a hydrogen of `X` by bromine atom gives one single bromoalkane. Hence, compound `X` is

A hydocarbon having molecular formula C_(8)H_(16) absorbed no hydrogen during hydrogenation. The hydrocarbon is

A hydrocarbon with molecular formula C_(8)H_(18) gives only one monochloro derivative. It can be :

A compound X has a molecular formula of C_(5)H_(10) . Write down the empirical formula of X.

An optically active hydrocarbon X has molecular formula C_(6)H_(12) . X on catalytic hydrogenation gives optically inactive C_(6)H_(14).X could be

An optically active hydrocarbon X has molecular formula C_(6)H_(12) . X on catalytic hydrogenation gives optically inactive C_(6)H_(14).X could be

A hydrocarbon with formula C_(8)H_(18) gives one monochloro derivative. The hydrocarbon can be:

A hydrocarbon with formula C_(8)H_(18) gives one monochloro derivative. The hydrocarbon can be:

Assign structures for the following: (a) An alkyne (X) has molecular formula C_(5) H_(8) . It reacts neither with sodamide nor with ammoniacal cuprous chloride. (b) A hydrocarbon Y decolourises bromine water. On ozonolysis it gives 3-methyl butanal and formaldehyde. Give the name of the compound. (c) A hydrocarbon (Z) has molecular formula C_(8)H_(10) . It does not decolourise bromine water and is oxidised to benzoic acid on heating with K_(2)Cr_(2)O_(7) . It can also have three other isomers A, B and C. Write the structures of Z, A, B and C.

A hydrocarbon has four carbon atoms.Give its molecular formula if it is an alkene?