In Fig `(QR)/(QS)=(QT)/(PR)= and angle1 = angle2.` show that `DeltaPQS ~DeltaTQR`.

In fig., (QR)/(QS)=(QT)/(PR) and angle1=angle2 . Show that trianglePQS~triangleTQR . .

In the given figure (QR)/(QS)=(QT)/(PR)" and "/_1= /_2 . Show that DeltaPQS ~ DeltaTQR .

In the given figure, (QT)/(PR) = (QR)/(QS) and angle 1 = angle 2 Prove that Delta PQS ~ Delta TQR .

In Fig . (QR)/(QS) = (QT)/(PR)and |__ul(1)=|__ul(2) . Show that Delta PQS ~ Delta TQR

In Fig. 6.36, (QR)/(QS)=(QT)/(PR) and angle 1=angle 2 .Show that trianglePQS~triangle TQR

In the given figure, (QR)/(QS)= (QT)/(PR) and angle1 = angle2 then prove that trianglePQS ~ triangleTQR.

In the figure beside , (QR)/(QS)=(QT)/(PR) and /_1=/_2 . Prove that DeltaPQS~DeltaTQR .

In the given figure, (QT)/(P)R = (QR)/(QS) and angle 1 = angle 2 . Prove that triangle PQS ~ triangle TQR .

In the given figure, S and T are points on sides PR and QR of Delta PQR such that angle P= angle RTS . Show that Delta RPQ~ Delta RTS .