If `pi/4

The principal value of tan^-1(-1) is [pi/4,-pi/4,pi-pi/4,pi+pi/4]

sin(pi)/(4)*sin(3 pi)/(4)*sin(5 pi)/(4)*sin(7 pi)/(4)=

f(x)=min(sin x,cos x),x in(-pi,pi) the values of x where f(x) is non differentiable,is the set A. Then A is subset of (A) {(-3 pi)/(4),(-pi)/(4),(3 pi)/(4)}(B){(-pi)/(4),(pi)/(4),(3 pi)/(3)}(C){(-3 pi)/(4),(3 pi)/(4)}(D){(-3 pi)/(4),(pi)/(4),(pi)/(4),(3 pi)/(4)}

A solution of the equation cos^(2)theta+s int h eta+1=0 lies in the interval (-pi/4,pi/4) b.(pi/4,3 pi/4)c(3 pi/4,5 pi/4)d*(5 pi/4,7 pi/4)

The solution o the equation cos^(2)theta+s int h eta+1=0 lies in the interval (-pi/4,pi/4) b.(pi/4,3 pi/4)c(3 pi/4,5 pi/4)d.(5 pi/4,7 pi/4)

A solution of the equation cos^2theta+sintheta+1=0 lies in the interval a. (-pi//4,pi//4) b. (pi//4,3pi//4) c. (3pi//4,5pi//4) d. (5pi//4,7pi//4)

Draw the graph of y= sqrt(2) sin (x+ (pi)/(4)) for the values of x= 0 , (pi)/(4) , (pi)/(2) ,(3pi)/(4) in [(pi)/(4) ,(3pi)/(4)] and find the maximum value of y.

For 0 cos^(-1)(sintheta) is true when theta belongs to (a) (pi/4,pi) (b) (pi,(3pi)/2) (c) (pi/4,(3pi)/4) (d) ((3pi)/4,2pi)

Prove that cos (pi/4-x) cos (pi/4-y)- sin (pi/4-x) sin(pi/4-y) =sin (x+y)

sin^(2)(pi)/(4)+sin^(2)(3 pi)/(4)+sin^(2)(5 pi)/(4)+sin^(2)(7 pi)/(4)=2