`sin(30^o +theta) +cos(60^o +theta)`:

Let f(theta) = sinthetaxx sin(60^@ + theta) sin(60^@ - theta) , then

Prove that sin (30^(@) + theta) + cos (60^(@) + theta) = cos theta

Evaluate sin(30^(@)+theta)-cos(60^(@)-theta) .

Evaluate sin(30^(@)+theta)-cos(60^(@)-theta) .

Prove the following identities: (i) costhetasin(90^o-theta)+sinthetacos(90^o-theta)=1 (ii) (sin(90^o-theta))sintheta/(tantheta)-1=-sin^2theta (iii) (sin(90^o-theta)cos(90^o-theta))/(tantheta)=1-sin^2theta

cos theta - cos (60^(@) + theta ) - cos(60^(@) - theta )=

cos theta cos (60^(@) + theta ) * cos (60^(@) - theta ) =

Find the value of sin(60+ theta )-cos(30-theta)

If sin (30 ^(@) - theta) = cos (60 ^(@) + phi) , then

I : cos^2 theta + cos^(2) (60^@ + theta ) + cos^(2) (60^@ - theta ) = 3//2 II : sin^(2) theta + sin^(2)(60^(@) + theta ) + sin^(2)(60^(@) - theta ) =3//2