A bullet of mass 20 kg travelling horizontally at `100 ms^(-1)` gets embedded at the centre of a block of wood of mass 1kg, suspended by a light vertical string of 1m in length. Calculate the maximum inclination of the string to the vertical.

A bullet of mass 10 g moving horizontally with a velocity of 400ms^(-1) strikes a wooden block of mass 2kg which is suspended by a light inextensible string of length 5 m. As a result, the centre of gravity of the block is found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be

A bullet of mass 10g moving horizontally with a velocity of 400 ms^-1 strikes a wooden block of mass 2kg which is suspended by a light inextensible string of length 5m .As a result , the centre of gravity of the block is found to rise a vertical distance of 10 cm . The speed of the bullet after it emerges out horizontally from thr block will be

A bullet of mass 10 g travels horizontally with a speed of 100 m*s^(-1) and penetrates in a wooden block of mass 990 g suspended by a string . Find the vertical height through which the block rises. Take g=10m*s^(-2) .