A hydrogen like atom number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. If it makes a transition ot quantum state n, a photon of energy 40.8 eV is emitted. Find n, Z and the ground state energy (in eV) of this atom. Also calculate the minimum energy of hydrogen atom is -13.6 ev.

A hydrogen like atom with atomic number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. If it makes a transition ot quantum state n, a photon of energy 40.8 eV is emitted. Find n, Z and the ground state energy (in eV) of this atom. Also calculate the minimum energy (in eV) that can be emitted by this atom during de-excitation. Ground state energy of hydrogen atom is – 13. 6 eV.

A hydrogen like atom with atomic number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. If it makes a transition ot quantum state n, a photon of energy 40.8 eV is emitted. Find n, Z and the ground state energy (in eV) of this atom. Also calculate the minimum energy (in eV) that can be emitted by this atom during de-excitation. Ground state energy of hydrogen atom is – 13. 6 eV.

A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n. It can emit a maximum energy photon of 204 eV. If it makes a transition to quantum state n, a photon of energy 40.8 eV is emitted. Find n, Z and the ground state energy (in eV) of this atom. Also calculate the minimum energy(eV) that can be emitted by this atom during de - excitation. Ground state energy of hydrogen atom is -13.6 eV

A hydrogen - like atom of atomic number Z is in an excited state of quantion number 2 n it can emit a maximum energy photon of energy 40.8 eV is emitted find n , Z and the ground state energy (in eV) for this atom . Also calculate the minimum energy (in eV) that can be emitted by this atom during de- exclation , Ground state energy of hydrogen atom is - 13.6 eV

A hydrogen atom is in a state of ionization energy 0.85 eV. If it makes a transition to the ground state, what is the energy of the emitted photon.

A hydrogen like atom (atomic number = Z) is in higher excited state of quantum number n. This excited atom can make a transition to first excited state by successively emitting two photons of energy 22.94 eV and 5.15 eV . The atom from the same state n can make transition to second excited state by successively emitting two photons of energies 2.4 eV and 8.7 eV . Find values of n and Z.

A hydrogen like atom (atomic number Z) is in a higher excited state of quantum number 'n' this excited atom can make a transition to the first excited state by emitting a photon of first 27.2eV . Alternatively the atom from the same excited state can make a transition of energy 10.20eV the value of n and z are given (ionization energy of hydrogen atom is 13.6eV)