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CH(3)Br +Nu^(Theta) rarr CH(3)-Nu +Br^(T...

`CH_(3)Br +Nu^(Theta) rarr CH_(3)-Nu +Br^(Theta)`
The decreasing order of the rate of the above reaction with nucleophiles `Nu^(Theta) A` to `D` is-
`[Nbar(u) =(A) phO^(-), (B) AcO^(-), (C)H bar(O),(D) CH_(3)bar(O)]`

A

`(D) gt (C) gt (A) gt (B)`

B

`(D) gt (C) gt (B) gt (A)`

C

`(C) gt (D) gt (A) gt (B)`

D

`(B) gt (D) gt (C) gt (A)`

Text Solution

Verified by Experts

The correct Answer is:
`c`

Acidic character:
`underset(pK_(a) "value:")() underset(4.75)(ACOH) gt underset(9.9)(PhOH) gt underset(15.5)(MeOH) gt underset(15.74)(H_(2)O)`
Basic and nucelphilic characters are same because of same nucleophilic centre.
Nucleophliic order:
`{:(AcO^(Theta),lt,PhO^(Theta),lt,MeO^(Theta),lt,overset(Theta)(O)H),((B),lt,(A),lt,(D),lt,(C)):}`
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CH_(3)Br+Nu^(-)rarrCH_(3)Nu+Br^(-) The decreasing order of the rate of the above reaction with nucleophiles (Nu^(-)) A to D is : [Nu^(-)=(A)PhO^(-),(B)AcO^(-),(C)HO^(-),(D)CH_(3)O^(-)]

Consider the following reaction, CH_(3)Br+Nu^(-)rarrCH_(3)-Nu+Br^(-) The decreasing order of the rate of the above reaction with Nu^(-) is I. PHO^(-) II. AcO^(-) III. HO^(-) IV. CH_(3)O^(-)

The increasing order of nucleophilicity of the following nucleophiles is: (a) CH_(3)CO_(2)^(-) (b) H_(2)O (c) CH_(3)SO_(3)^(-) (d) overset(O)H

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