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HBr reacts with CH(2)=CH-OCH(3) under an...

`HBr` reacts with `CH_(2)=CH-OCH_(3)` under anhydrous conditions at room temperature to give:

A

`CH_(3)CHO` and `CH_(3)Br`

B

`BrCH_(2)CHO` and `CH_(3)OH`

C

`BrCH_(2)CH_(2)OCH_(3)`

D

`CH_(3) - CH(Br) - OCH_(3)`

Text Solution

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The correct Answer is:
`d`
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