Solve `(tan 3x - tan 2x)/(1+tan 3x tan 2x)=1`.

Solve (tan3x-tan2x)/(1+tan3x tan2x')=1

Find the set of values of x for which (tan 3x - tan 2x)/ (1+ tan3x tan 2x) = 1

The set of values of x, for which (tan 3x - tan 2x)/(1+tan 3x tan 2x)=1 is

Find the set of values of x for which (tan 3x - tan 2x)/(1 + tan 3x cdot tan 2x) = 1

Solve (tan3x-tan2x)/(1+tan3xtan2x ')=1

Solve (tan3x-tan2x)/(1+tan3xtan2x )=1

Solve (tan3x-tan2x)/(1+tan3xtan2x )=1

Solve (tan3x-tan2x)/(1+tan3xtan2x )=1

A : The set values of x for which (tan 3x-tan 2x)/(1+tan 3x tan 2x)=1 is Ø R : tan x is undefined at x = pi//2