A block of mass 5 kg and surface area `2m^(2)` just begins to slide down an inclined plane when the angle on inclination is `30^(@)`. Keeping mass same, the surface area of the block is doubled. The angle is which this starts sliding down is

A block of mass m and surface area A just begins to slide down an inclined plane when the angle of inclination is pi//5 . Keeping the mass of the block same, if the surface area is doubled the inclination of the plane at which the block starts sliding will be .

A block of mass 10 kg is placed on an inclined plane when the angle of inclination is 30^(@) . The block just begins to slide down the plane. The force of static friction is

A block of mas m begins to slide down on an inclined plane of inclination theta . The force of friction will be

A block slides down on inclined plane (angle of inclination 60^(@) ) with an accelration g//2 Find the coefficient friction

A block slides down on inclined plane (angle of inclination 60^(@) ) with an accelration g//2 Find the coefficient friction