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I. x ^(2) + 5x + 6 = 0 II. y^(2) + 3y...

I. ` x ^(2) + 5x + 6 = 0`
II. `y^(2) + 3y +2 = 0`

A

if ` x gt y`

B

if `x ge y`

C

if ` x lt y`

D

if ` x le y`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given equations and find the relationship between \( x \) and \( y \), we will follow these steps: ### Step 1: Solve the first equation \( x^2 + 5x + 6 = 0 \) 1. **Identify the quadratic equation**: The equation is in the standard form \( ax^2 + bx + c = 0 \), where \( a = 1 \), \( b = 5 \), and \( c = 6 \). 2. **Factor the quadratic**: We need to factor the equation. We look for two numbers that multiply to \( c \) (6) and add to \( b \) (5). The numbers are 2 and 3. \[ x^2 + 5x + 6 = (x + 2)(x + 3) = 0 \] 3. **Set each factor to zero**: \[ x + 2 = 0 \quad \Rightarrow \quad x = -2 \] \[ x + 3 = 0 \quad \Rightarrow \quad x = -3 \] 4. **Solutions for \( x \)**: The solutions are \( x = -2 \) and \( x = -3 \). ### Step 2: Solve the second equation \( y^2 + 3y + 2 = 0 \) 1. **Identify the quadratic equation**: The equation is in the standard form \( ay^2 + by + c = 0 \), where \( a = 1 \), \( b = 3 \), and \( c = 2 \). 2. **Factor the quadratic**: We look for two numbers that multiply to \( c \) (2) and add to \( b \) (3). The numbers are 1 and 2. \[ y^2 + 3y + 2 = (y + 1)(y + 2) = 0 \] 3. **Set each factor to zero**: \[ y + 1 = 0 \quad \Rightarrow \quad y = -1 \] \[ y + 2 = 0 \quad \Rightarrow \quad y = -2 \] 4. **Solutions for \( y \)**: The solutions are \( y = -1 \) and \( y = -2 \). ### Step 3: Determine the relationship between \( x \) and \( y \) 1. **List the values**: - From the first equation, \( x \) can be \( -2 \) or \( -3 \). - From the second equation, \( y \) can be \( -1 \) or \( -2 \). 2. **Compare the values**: - If \( x = -2 \), then \( y = -2 \) (which means \( x = y \)). - If \( x = -3 \), then \( y = -1 \) (which means \( x < y \)). 3. **Conclusion**: The relationship can be summarized as: - \( x \) can be equal to \( y \) when both are \( -2 \). - \( x \) is less than \( y \) when \( x = -3 \) and \( y = -1 \). ### Final Result: The relationship between \( x \) and \( y \) can be expressed as: - \( x \leq y \) ---

To solve the given equations and find the relationship between \( x \) and \( y \), we will follow these steps: ### Step 1: Solve the first equation \( x^2 + 5x + 6 = 0 \) 1. **Identify the quadratic equation**: The equation is in the standard form \( ax^2 + bx + c = 0 \), where \( a = 1 \), \( b = 5 \), and \( c = 6 \). 2. **Factor the quadratic**: We need to factor the equation. We look for two numbers that multiply to \( c \) (6) and add to \( b \) (5). The numbers are 2 and 3. \[ x^2 + 5x + 6 = (x + 2)(x + 3) = 0 ...
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