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I. x^(2) +20x + 4 = 50 -25x II. y^(2...

I. ` x^(2) +20x + 4 = 50 -25x`
II. ` y^(2) - 10y - 24 = 0`

A

if ` x gt y`

B

if `x lt y`

C

if `x ge y`

D

if `x le y`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given equations step by step, we will first tackle each equation separately and then find the relationship between the values of \(x\) and \(y\). ### Step 1: Solve the first equation The first equation is: \[ x^2 + 20x + 4 = 50 - 25x \] **Step 1.1:** Rearrange the equation We will move all terms to one side of the equation: \[ x^2 + 20x + 25x + 4 - 50 = 0 \] This simplifies to: \[ x^2 + 45x - 46 = 0 \] **Step 1.2:** Factor the quadratic equation We need to factor the quadratic equation \(x^2 + 45x - 46 = 0\). We look for two numbers that multiply to \(-46\) and add to \(45\). The numbers are \(46\) and \(-1\): \[ (x + 46)(x - 1) = 0 \] **Step 1.3:** Find the values of \(x\) Setting each factor to zero gives us: 1. \(x + 46 = 0 \Rightarrow x = -46\) 2. \(x - 1 = 0 \Rightarrow x = 1\) So, the values of \(x\) are: \[ x = -46 \quad \text{and} \quad x = 1 \] ### Step 2: Solve the second equation The second equation is: \[ y^2 - 10y - 24 = 0 \] **Step 2.1:** Factor the quadratic equation We look for two numbers that multiply to \(-24\) and add to \(-10\). The numbers are \(-12\) and \(2\): \[ (y - 12)(y + 2) = 0 \] **Step 2.2:** Find the values of \(y\) Setting each factor to zero gives us: 1. \(y - 12 = 0 \Rightarrow y = 12\) 2. \(y + 2 = 0 \Rightarrow y = -2\) So, the values of \(y\) are: \[ y = 12 \quad \text{and} \quad y = -2 \] ### Step 3: Determine the relationship between \(x\) and \(y\) Now we have the values: - \(x = -46\) or \(x = 1\) - \(y = 12\) or \(y = -2\) **Step 3.1:** Compare the values 1. If \(x = -46\): - Compare with \(y = 12\): \(-46 < 12\) - Compare with \(y = -2\): \(-46 < -2\) 2. If \(x = 1\): - Compare with \(y = 12\): \(1 < 12\) - Compare with \(y = -2\): \(1 > -2\) ### Conclusion From the comparisons: - In both cases, \(x\) is less than \(y\) when \(y = 12\). - When \(y = -2\), \(x = 1\) is greater than \(y\). Thus, the relationship between \(x\) and \(y\) can be summarized as: - \(x\) is less than \(y\) when \(y = 12\). ### Final Answer The relationship can be stated as: - \(x < y\) when \(y = 12\).

To solve the given equations step by step, we will first tackle each equation separately and then find the relationship between the values of \(x\) and \(y\). ### Step 1: Solve the first equation The first equation is: \[ x^2 + 20x + 4 = 50 - 25x \] **Step 1.1:** Rearrange the equation We will move all terms to one side of the equation: ...
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