I.` 8/sqrtX+6/sqrtX = sqrtX`
II.` y^(2) -(14^(5//2)//Y^(1//2)) = 0`

Options

A. ` x gt y`
B. ` x ge y`
C. ` x lt y`
D. x = y or a relationship between x and y cannot be established.

Explanation

Let's solve the equations step by step.

### Part I: Solve for x

1. **Given Equation**:
\[ \frac{8}{\sqrt{x}} + \frac{6}{\sqrt{x}} = \sqrt{x} \]

2. **Combine the fractions on the left side**:
\[ \frac{8 + 6}{\sqrt{x}} = \sqrt{x} \]
This simplifies to:
\[ \frac{14}{\sqrt{x}} = \sqrt{x} \]

3. **Cross-multiply**:
\[ 14 = \sqrt{x} \cdot \sqrt{x} \]
This means:
\[ 14 = x \]

### Part II: Solve for y

1. **Given Equation**:
\[ y^2 - \frac{14^{5/2}}{y^{1/2}} = 0 \]

2. **Rearranging the equation**:
\[ y^2 = \frac{14^{5/2}}{y^{1/2}} \]

3. **Multiply both sides by \(y^{1/2}\)** to eliminate the fraction:
\[ y^{2} \cdot y^{1/2} = 14^{5/2} \]
This simplifies to:
\[ y^{2 + 1/2} = 14^{5/2} \]
Which is:
\[ y^{5/2} = 14^{5/2} \]

4. **Since the bases are equal, equate the exponents**:
\[ y = 14 \]

### Conclusion

Now we have found:
- \(x = 14\)
- \(y = 14\)

Thus, we can conclude that:
\[ x = y \]