Sujata scored 2240 marks in an examination that is 128 marks more than the minimum passing percentage of 64% . What is the percentage of marks obtained by Meena if she scores 907 marks less than Sujata ?

Options

A. 35
B. 40
C. 45
D. 36

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Determine the Total Marks
We know that Sujata scored 2240 marks, which is 128 marks more than the minimum passing marks. The minimum passing percentage is 64%.

Let the total marks be \( T \).

The minimum passing marks can be calculated as:
\[ \text{Minimum Passing Marks} = 0.64 \times T \]
Since Sujata scored 128 marks more than this, we can set up the equation:
\[ 2240 = 0.64T + 128 \]

### Step 2: Solve for Total Marks \( T \)
Rearranging the equation:
\[ 0.64T = 2240 - 128 \]
\[ 0.64T = 2112 \]
Now, divide both sides by 0.64 to find \( T \):
\[ T = \frac{2112}{0.64} \]
Calculating this gives:
\[ T = 3300 \]

### Step 3: Calculate Meena's Score
Meena scored 907 marks less than Sujata. So, we calculate Meena's score as follows:
\[ \text{Meena's Score} = 2240 - 907 \]
Calculating this gives:
\[ \text{Meena's Score} = 1333 \]

### Step 4: Calculate the Percentage of Marks Obtained by Meena
To find the percentage of marks obtained by Meena, we use the formula:
\[ \text{Percentage} = \left(\frac{\text{Meena's Score}}{\text{Total Marks}}\right) \times 100 \]
Substituting the values we have:
\[ \text{Percentage} = \left(\frac{1333}{3300}\right) \times 100 \]
Calculating this gives:
\[ \text{Percentage} \approx 40.39\% \]

### Final Answer
Meena scored approximately **40.39%** of the total marks.

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