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Pipes A can fill a tank in 30 minutes wh...

Pipes A can fill a tank in 30 minutes while pipe B can fill it in 45
minutes. An other pipe C can empty a full tank in 60 minutes.
If all three pipes are opened simultaneously, The empty tank
will be filled in

A

`2/7` hour

B

`3/7` hour

C

`4/7` hour

D

`5/7` hour

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how long it will take to fill an empty tank when three pipes (A, B, and C) are opened simultaneously. Here’s a step-by-step solution: ### Step 1: Determine the filling and emptying rates of the pipes. - **Pipe A** can fill the tank in 30 minutes. Therefore, its rate is: \[ \text{Rate of A} = \frac{1 \text{ tank}}{30 \text{ minutes}} = \frac{1}{30} \text{ tanks per minute} \] - **Pipe B** can fill the tank in 45 minutes. Therefore, its rate is: \[ \text{Rate of B} = \frac{1 \text{ tank}}{45 \text{ minutes}} = \frac{1}{45} \text{ tanks per minute} \] - **Pipe C** can empty the tank in 60 minutes. Therefore, its rate is: \[ \text{Rate of C} = \frac{1 \text{ tank}}{60 \text{ minutes}} = \frac{1}{60} \text{ tanks per minute} \] Since it is emptying the tank, we will consider this rate as negative: \[ \text{Rate of C} = -\frac{1}{60} \text{ tanks per minute} \] ### Step 2: Calculate the combined rate of all three pipes. The combined rate when all three pipes are opened simultaneously is: \[ \text{Combined Rate} = \text{Rate of A} + \text{Rate of B} + \text{Rate of C} \] Substituting the values we calculated: \[ \text{Combined Rate} = \frac{1}{30} + \frac{1}{45} - \frac{1}{60} \] ### Step 3: Find a common denominator and simplify. The least common multiple (LCM) of 30, 45, and 60 is 180. We will convert each rate to have this common denominator: - For Pipe A: \[ \frac{1}{30} = \frac{6}{180} \] - For Pipe B: \[ \frac{1}{45} = \frac{4}{180} \] - For Pipe C: \[ -\frac{1}{60} = -\frac{3}{180} \] Now, substituting these into the combined rate: \[ \text{Combined Rate} = \frac{6}{180} + \frac{4}{180} - \frac{3}{180} = \frac{6 + 4 - 3}{180} = \frac{7}{180} \text{ tanks per minute} \] ### Step 4: Calculate the time to fill the tank. To find the time taken to fill one tank, we take the reciprocal of the combined rate: \[ \text{Time} = \frac{1 \text{ tank}}{\frac{7}{180} \text{ tanks per minute}} = \frac{180}{7} \text{ minutes} \] ### Step 5: Convert the time into hours and minutes. Calculating \( \frac{180}{7} \): \[ \frac{180}{7} \approx 25.71 \text{ minutes} \] This can be converted into hours and minutes: - 25 minutes and \( 0.71 \times 60 \approx 42.86 \) seconds, which is approximately 43 seconds. Thus, the tank will be filled in approximately **25 minutes and 43 seconds**. ### Final Answer: The empty tank will be filled in approximately **25 minutes and 43 seconds**.

To solve the problem, we need to determine how long it will take to fill an empty tank when three pipes (A, B, and C) are opened simultaneously. Here’s a step-by-step solution: ### Step 1: Determine the filling and emptying rates of the pipes. - **Pipe A** can fill the tank in 30 minutes. Therefore, its rate is: \[ \text{Rate of A} = \frac{1 \text{ tank}}{30 \text{ minutes}} = \frac{1}{30} \text{ tanks per minute} \] ...
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