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A, b and C can alone complete a work in ...

A, b and C can alone complete a work in 10, 12 and 15 days
respectively. A and C started the work and after working for
4 days, A left and B joined. In how many days the total work
was completed ?

A

`6 5/9 days `

B

` 6 2/9 days `

C

6 days

D

` 5 4/9 days `

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Determine the work done by A, B, and C in one day. - A can complete the work in 10 days, so A's work in one day = \( \frac{1}{10} \) of the work. - B can complete the work in 12 days, so B's work in one day = \( \frac{1}{12} \) of the work. - C can complete the work in 15 days, so C's work in one day = \( \frac{1}{15} \) of the work. ### Step 2: Convert the work done in one day into a common unit. To make calculations easier, we can find a common denominator. The least common multiple of 10, 12, and 15 is 60. Therefore: - A's work in one day = \( \frac{60}{10} = 6 \) units. - B's work in one day = \( \frac{60}{12} = 5 \) units. - C's work in one day = \( \frac{60}{15} = 4 \) units. ### Step 3: Calculate the total work done by A and C in 4 days. - A and C together can do \( 6 + 4 = 10 \) units of work in one day. - In 4 days, they will complete \( 10 \times 4 = 40 \) units of work. ### Step 4: Determine the remaining work after A and C have worked for 4 days. - Total work = 60 units. - Work done by A and C in 4 days = 40 units. - Remaining work = \( 60 - 40 = 20 \) units. ### Step 5: Calculate the work done by B and C together. - After 4 days, A leaves and B joins C. - B and C together can do \( 5 + 4 = 9 \) units of work in one day. ### Step 6: Calculate the number of days required to complete the remaining work. - Remaining work = 20 units. - Work done by B and C in one day = 9 units. - Days required to finish the remaining work = \( \frac{20}{9} \) days. ### Step 7: Calculate the total time taken to complete the work. - Total time = 4 days (A and C working) + \( \frac{20}{9} \) days (B and C working). - To combine these, we convert 4 days into a fraction: \( 4 = \frac{36}{9} \). - Total time = \( \frac{36}{9} + \frac{20}{9} = \frac{56}{9} \) days. ### Final Answer: The total work was completed in \( \frac{56}{9} \) days, which is approximately 6.22 days. ---

To solve the problem step by step, we will follow these steps: ### Step 1: Determine the work done by A, B, and C in one day. - A can complete the work in 10 days, so A's work in one day = \( \frac{1}{10} \) of the work. - B can complete the work in 12 days, so B's work in one day = \( \frac{1}{12} \) of the work. - C can complete the work in 15 days, so C's work in one day = \( \frac{1}{15} \) of the work. ### Step 2: Convert the work done in one day into a common unit. ...
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