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The sides of a triangular field are 41 m...

The sides of a triangular field are 41 m, 40 m and 9 m. The number of rose beds that can be prepared in the field if each rose bed, on an average, needs 900 square cm space,

A

2000

B

1800

C

900

D

800

Text Solution

Verified by Experts

The correct Answer is:
A

Area of triangular field
`sqrt(s(s-a)(s-b)(s-c))`
`s=(a+b+c)/2=(41+40+9)/2=45m`
`"Area"=sqrt(45xx(45-41)xx(45-40)xx(45-9))`
`=sqrt(45xx4xx5xx36)=180m^2=1800000cm^2`
Number of rose bed `=1800000/900=2000.`
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