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1kg ice at 0^(@)C is mixed with 1kg of s...

`1kg` ice at `0^(@)C` is mixed with `1kg` of steam at `100^(@)C` what will be the composition of the system when thermal equilibrium is reached ? Latent beat of fusion of ice `= 3.36xx 10^(5)J kg^(-1)` and latent head of vaporization of water `= 2.26 xx 10^(6)J kg^(-1)`

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1kg ice at 0^(@)C is mixed with 1kg of steam at 100^(@)C . What will be the composition of the system when thermal equilibrium is reached ? Latent heat of fusion of ice = 3.36xx 10^(6)J kg^(-1) and latent heat of vaporization of water = 2.26 xx 10^(6)J kg^(-1)

1kg ice at 0^(@)C is mixed with 1kg of steam at 100^(@)C . What will be the composition of the system when thermal equilibrium is reached ? Latent heat of fusion of ice = 3.36xx 10^(6)J kg^(-1) and latent heat of vaporization of water = 2.26 xx 10^(6)J kg^(-1)

1kg ice at 0^(@)C is mixed with 1kg of steam at 100^(@)C . What will be the composition of the system when thermal equilibrium is reached ? Latent heat of fusion of ice = 3.36xx 10^(6)J kg^(-1) and latent heat of vaporization of water = 2.26 xx 10^(6)J kg^(-1)

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1kg ice at -10^(@)C is mixed with 1kg water at 100^(@)C . Then final equilirium temperature and mixture content.

1kg ice at -10^(@)C is mixed with 1kg water at 100^(@)C . Then final equilirium temperature and mixture content.